Logical Reasoning - Letter and Symbol Series - Discussion
Discussion Forum : Letter and Symbol Series - Type 1 (Q.No. 2)
Directions to Solve
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
2.
B2CD, _____, BCD4, B5CD, BC6D
Answer: Option
Explanation:
Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.
Discussion:
46 comments Page 2 of 5.
Anjali said:
9 years ago
Steps.
1. Give number to all alphabets as 1, 2, 3, 4 (a-1, b-2, c-3).
2. You will notice that number series 234 is repeated.
3. Observe that in the first set, the first alphabet is repeated 2 times, in the second set should repeat. Times, in third series third alphabet is repeated four time. The circle is repeated with increasing number of repeating alphabet. So at the blank space second alphabet should repeat 3 times.
1. Give number to all alphabets as 1, 2, 3, 4 (a-1, b-2, c-3).
2. You will notice that number series 234 is repeated.
3. Observe that in the first set, the first alphabet is repeated 2 times, in the second set should repeat. Times, in third series third alphabet is repeated four time. The circle is repeated with increasing number of repeating alphabet. So at the blank space second alphabet should repeat 3 times.
(2)
Swati said:
9 years ago
Please explain the last term.
(2)
Nithin said:
9 years ago
I didn't get logic, please explain me.
(3)
Krishna said:
9 years ago
B2CD, -------, BCD4, B5CD, BC6D.
SOLVE,
2+1=3 after one word BC3D.
3+1=4 after one word BCD4.
4+1=5 after one word (repeat from first word because D is end) B5CD.
5+1=6 after one word BC6D.
SOLVE,
2+1=3 after one word BC3D.
3+1=4 after one word BCD4.
4+1=5 after one word (repeat from first word because D is end) B5CD.
5+1=6 after one word BC6D.
(1)
Prakash said:
10 years ago
Someone please explain me to get the answer.
(1)
Pandu said:
10 years ago
How will come? please explain.
GOMATHI said:
10 years ago
On this letter series the number will take b to c, and c to d, and again d to b like triangle wise. So first, b series they had been mentioned the substring of 2. So, what will happen, next to b, c series will get the next process, after that d, next c.
WILLIAMKERY said:
1 decade ago
First number B2CD = B + B + C + D = 4 "B2". First series start with 2.
Second number BC3D = B + C + C + C +D = 5 "C3". Second series Sequence 3.
Third Numbr BCD4 = B + C + D + D + D + D = 6 "D4" Third Series sequence 4.
Fourth Number B5CD = B + B + B + B + B + C + D =7 "B5" Alternator continue with number 5.
Fifth number BC6D =B +C + C + C + C + C + C + D =8 "C6" This the sequence with 6.
Second number BC3D = B + C + C + C +D = 5 "C3". Second series Sequence 3.
Third Numbr BCD4 = B + C + D + D + D + D = 6 "D4" Third Series sequence 4.
Fourth Number B5CD = B + B + B + B + B + C + D =7 "B5" Alternator continue with number 5.
Fifth number BC6D =B +C + C + C + C + C + C + D =8 "C6" This the sequence with 6.
(1)
Harsha said:
1 decade ago
@Rubini tell me about the your answer.
Harsha said:
1 decade ago
I can't understand this logic.
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