Java Programming - Operators and Assignments - Discussion
Discussion Forum : Operators and Assignments - Finding the output (Q.No. 1)
1.
What will be the output of the program?
class PassA
{
public static void main(String [] args)
{
PassA p = new PassA();
p.start();
}
void start()
{
long [] a1 = {3,4,5};
long [] a2 = fix(a1);
System.out.print(a1[0] + a1[1] + a1[2] + " ");
System.out.println(a2[0] + a2[1] + a2[2]);
}
long [] fix(long [] a3)
{
a3[1] = 7;
return a3;
}
}
Answer: Option
Explanation:
Output: 15 15
The reference variables a1 and a3 refer to the same long array object. When the [1] element is updated in the fix() method, it is updating the array referred to by a1. The reference variable a2 refers to the same array object.
So Output: 3+7+5+" "3+7+5
Output: 15 15 Because Numeric values will be added
Discussion:
43 comments Page 3 of 5.
Salik Khan said:
5 years ago
It's because in java array is passed by reference, so any changes in the method reflect in the actual array.
Aryan Sahebrao Salunkhe said:
2 years ago
Good, thanks all for explaining.
Nadeem said:
1 decade ago
How is 15 printed even if we are not performing addition of a1 and a2 elements anywhere?
Ram said:
1 decade ago
The method fix()is fixed the is a3[1]=7, so that value is assing by the position of a[1]=7.
Vasu said:
1 decade ago
While program is executing
ofter second step
the method of fix(_)
then it comes again back to 3 step.
so it changes the array elements in the position of 1
i.e (a1[1])
ofter second step
the method of fix(_)
then it comes again back to 3 step.
so it changes the array elements in the position of 1
i.e (a1[1])
Vagmita said:
1 decade ago
I cant understand fix... method...
Sainath said:
1 decade ago
Can anyone explain me in clear way?
Gopi said:
1 decade ago
@Naga. It's because of reflection in referenced object.
Vijay said:
1 decade ago
3 elements should be printed know why only 2 elements are being printed
When I give like this
System.out.print("a1[0]"+a1[0] +"a1[1]"+ a1[1] +"a1[2]"+ a1[2] + " ");
Then it will give the result as
a1[0] = 3
a1[1] = 7
a1[2] = 5 this is why.
When I give like this
System.out.print("a1[0]"+a1[0] +"a1[1]"+ a1[1] +"a1[2]"+ a1[2] + " ");
Then it will give the result as
a1[0] = 3
a1[1] = 7
a1[2] = 5 this is why.
Prudhvi Kumar said:
1 decade ago
Please any one explain me output for this program and fix method in-detail.
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