Java Programming - Operators and Assignments - Discussion

In C, we have pointers to get the address of a variable. But in java pointers concept is not there but java has indirectly using pointers such as objects. Objects are nothing but references. So the array is a class of object in java. That's why a1 affected by the method fix().

Here, fix(a1) is for a2, so why a1[1] in a[1] change to 7 while a1 doesn't use fix method?

What is role of fix()?

What is role of fix()?

The reason why is because arrays are not primitive types.

Primitive types: pass copy of variable to parameter.

Objects(user defined types): pass by reference variable/objects as parameter.

There are exceptions to arrays(int[],long[], etc).

Formally speaking, an array is a reference type, though you cannot find such a class in the Java APIs.

According to me,

class PassA
{
public static void main(String [] args)
{
PassA p = new PassA();
p.start();
}

void start()
{
long [] a1 = {3,4,5};
long [] a2 = fix(a1);// In this line we are sending the reference variable of a1.
System.out.print(a1[0] + a1[1] + a1[2] + " ");
System.out.println(a2[0] + a2[1] + a2[2]);
}

long [] fix(long [] a3) // Now a3 also starts pointing to the same array as a1 is pointing.
{
a3[1] = 7;// Any modification done now will reflect on both a1..
return a3;//After returning this value array a2 starts will start to point a1 array as well.
}
}

fix() is from which package? Please explain.

long[] fix(long[] a3) { // a3=a1 and a1= {3,4,5}
a3[1] = 7; // a3[1]=7 means a1[1] will become 7(a1[1]=7), now a1={3,7,5}
return a3;// return a1
}

How the value of A1[1] has changed? explain.

Please tell me how to work bubble sort method with easy program? Please explain with an example.