Java Programming - Operators and Assignments - Discussion

Discussion Forum : Operators and Assignments - Finding the output (Q.No. 4)
4.
What will be the output of the program?
class BitShift 
{
    public static void main(String [] args) 
    {
        int x = 0x80000000;
        System.out.print(x + " and  ");
        x = x >>> 31;
        System.out.println(x);
    }
}
-2147483648 and 1
0x80000000 and 0x00000001
-2147483648 and -1
1 and -2147483648
Answer: Option
Explanation:

Option A is correct. The >>> operator moves all bits to the right, zero filling the left bits. The bit transformation looks like this:

Before: 1000 0000 0000 0000 0000 0000 0000 0000

After: 0000 0000 0000 0000 0000 0000 0000 0001

Option C is incorrect because the >>> operator zero fills the left bits, which in this case changes the sign of x, as shown.

Option B is incorrect because the output method print() always displays integers in base 10.

Option D is incorrect because this is the reverse order of the two output numbers.

Discussion:
17 comments Page 1 of 2.

Sangeetha said:   7 years ago
Thanks for your explanation @Fakru.
(1)

Manisha said:   7 years ago
How to convert 0x80000000 in hexadecimal to decimal?
Can you explain the process?
What is the value of x?

Abhi said:   8 years ago
How can we say 0x80000000 as hexadecimal value?

LIYAKAT said:   8 years ago
It's really helpful. Thanks.

Fakru said:   8 years ago
If you convert 0x80000000 (which is in hexadecimal form) to decimal form, it gives 2147483648. But, the range of integer in java is -2147483648 to 2147483647.

Since, the converted decimal value exceeds the range(positive value) of integer, it takes the negative value and the values go in a cycle from positive to negative. As the converted decimal value exceeds the integer range by 1, the 1st value from -2147483648 is taken, which is -2147483648.
(1)

Nagalakshmi said:   9 years ago
How to convert hexadecimal to decimal such huge number very quickly?

Please give me the short method.

Shubham said:   9 years ago
Can anyone explain clearly how this answer came?

Amar said:   9 years ago
But hexadecimal representation of Number allow only 4 Digits after 0X?

Divya said:   9 years ago
Can anyone please explain it in detail?

Keshav Kumar said:   9 years ago
Binary equivalent of 0X80000000 is 10000000000000000000000000000000. In int data type if 32nd bit is off, then decimal equivalent is positive and if 32nd bit is on then the equivalent is negative.


Post your comments here:

Your comments will be displayed after verification.