Java Programming - Language Fundamentals - Discussion
- char c1 = 064770;
- char c2 = 'face';
- char c3 = 0xbeef;
- char c4 = \u0022;
- char c5 = '\iface';
- char c6 = '\uface';
(1), (3), and (6) are correct. char c1 = 064770; is an octal representation of the integer value 27128, which is legal because it fits into an unsigned 16-bit integer. char c3 = 0xbeef; is a hexadecimal representation of the integer value 48879, which fits into an unsigned 16-bit integer. char c6 = '\uface'; is a Unicode representation of a character.
char c2 = 'face'; is wrong because you can't put more than one character in a char literal. The only other acceptable char literal that can go between single quotes is a Unicode value, and Unicode literals must always start with a '\u'.
char c4 = \u0022; is wrong because the single quotes are missing.
char c5 = '\iface'; is wrong because it appears to be a Unicode representation (notice the backslash), but starts with '\i' rather than '\u'.
But while displaying values, it displays only ? for statements..
Why it displaying like that......
Any one please post the answer for this...
Why char c2='face'; is wrong answer?
Please justified it.
c2='a' it is represntaion of character.
But, in the given question c2='face' trying to assign the string value to character variable.