Java Programming - Java.lang Class - Discussion
Discussion Forum : Java.lang Class - Finding the output (Q.No. 7)
7.
What will be the output of the program?
String x = "xyz";
x.toUpperCase(); /* Line 2 */
String y = x.replace('Y', 'y');
y = y + "abc";
System.out.println(y);
Answer: Option
Explanation:
Line 2 creates a new String object with the value "XYZ", but this new object is immediately lost because there is no reference to it. Line 3 creates a new String object referenced by y. This new String object has the value "xyz" because there was no "Y" in the String object referred to by x. Line 4 creates a new String object, appends "abc" to the value "xyz", and refers y to the result.
Discussion:
6 comments Page 1 of 1.
RIYAZ said:
3 years ago
D is the right option.
Namitha said:
7 years ago
Sysout statement should display the value of y as xyz.
I feel cos y= y+ abc would be lost.
I feel cos y= y+ abc would be lost.
Manoj said:
9 years ago
As there is no reference created after x=x.toUpperCase(); statement.
So the answer will be xyzabc.
So the answer will be xyzabc.
Atika said:
9 years ago
Why not the answer is option D?
Mayur said:
1 decade ago
Ya its correct now.xyx is converted to XYZ and is overwritten in x.nexY is replaced by y and then XyZ is concatenated with abc as + orks as concatenantion operator in Java with string types
Pratik patel said:
1 decade ago
String x = "xyz";
x=x.toUpperCase();
String y = x.replace('Y', 'y');
y = y + "abc";
System.out.println(y);
now o/p is XyZabc is it true??
x=x.toUpperCase();
String y = x.replace('Y', 'y');
y = y + "abc";
System.out.println(y);
now o/p is XyZabc is it true??
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers