Java Programming - Java.lang Class - Discussion
Discussion Forum : Java.lang Class - General Questions (Q.No. 4)
4.
public class Myfile
{
public static void main (String[] args)
{
String biz = args[1];
String baz = args[2];
String rip = args[3];
System.out.println("Arg is " + rip);
}
}
Answer: Option
Explanation:
Arguments start at array element 0 so the fourth arguement must be 2 to produce the correct output.
Discussion:
33 comments Page 3 of 4.
Santhosh said:
1 decade ago
What about option 4 ?
Gaurav singh said:
1 decade ago
public class Test
{
public static void main (String[] args)
{
String biz = args[1];
String baz = args[2];
String rip = args[3];
System.out.println("Arg is " + rip);
}
}
the o/p needed is--> Arg is 2.
i.e. 2 is at the rip place.
And rip is args[3] i.e 4th place.
Because cmd line arg start with 0,1,2,3,4 and so on.
Hence in the option we need 2 at the 4th place.
That's why the ans is 1 3 2 2.
{
public static void main (String[] args)
{
String biz = args[1];
String baz = args[2];
String rip = args[3];
System.out.println("Arg is " + rip);
}
}
the o/p needed is--> Arg is 2.
i.e. 2 is at the rip place.
And rip is args[3] i.e 4th place.
Because cmd line arg start with 0,1,2,3,4 and so on.
Hence in the option we need 2 at the 4th place.
That's why the ans is 1 3 2 2.
Aanand said:
1 decade ago
Answer C is right.
args[0]=1;
args[1]=3;
args[2]=2;
args[3]=2;
Please do not get confused with args[0] = java and args[1] = Myfile . This is true in C but not in java. In java , command line arguments till application name (here Myfile) is not the part of array args.
args[0]=1;
args[1]=3;
args[2]=2;
args[3]=2;
Please do not get confused with args[0] = java and args[1] = Myfile . This is true in C but not in java. In java , command line arguments till application name (here Myfile) is not the part of array args.
Anvesh said:
1 decade ago
Yes dude,actually this is command line args, so normally arrays will be starting with zero, so given that answer c is correct, how means
args[1]=0;
args[2]=1;
args[3]=2;
So this args[3] value will be coming with we are using command line args. First you learn command line args carefully.
args[1]=0;
args[2]=1;
args[3]=2;
So this args[3] value will be coming with we are using command line args. First you learn command line args carefully.
Subhan said:
1 decade ago
Anybody can explain this code clearly please I can't understand
Arindam said:
1 decade ago
When we want to run a java program then we always use
"java main_class_name"
But you use something more then that are stored in args[] array, which is also known as command line argument....
For ex- i write "java main_class_name Arindam Ghosh"
then program will run but 'Arindam' will stored in args[0] and 'Ghosh' will stored in args[1];
That's why here rip=args[3]=2
args[0]=1
args[1]=3
args[2]=2
args[3]=2
"java main_class_name"
But you use something more then that are stored in args[] array, which is also known as command line argument....
For ex- i write "java main_class_name Arindam Ghosh"
then program will run but 'Arindam' will stored in args[0] and 'Ghosh' will stored in args[1];
That's why here rip=args[3]=2
args[0]=1
args[1]=3
args[2]=2
args[3]=2
Asoka said:
1 decade ago
I think [B] is correct answer!
The same with Sundar!
The same with Sundar!
Sundar said:
1 decade ago
The given answer is correct. I have tested the same.
Hope this will help you. Have a nice day!
D:\Siva\Java>type Test.java
public class Test
{
public static void main (String[] args)
{
String biz = args[1];
String baz = args[2];
String rip = args[3];
System.out.println("Arg is " + rip);
}
}
D:\Siva\Java>javac Test.java
D:\Siva\Java>java Test 1 3 2 2
Arg is 2
D:\Siva\Java>Hope this will help you. Have a nice day!
Sreekanth said:
1 decade ago
Actually if you check here as explained by args[0] = java args[1] = Myfile args[2] = 1 and args[3] = 3.
So the answer is not a correct one.
So the answer is not a correct one.
Akash Gupta said:
1 decade ago
This is very cconfusinig,i can't satisfied with your sugesition.
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