Java Programming - Java.lang Class - Discussion

Very confusing, somebody please help me.

public class Test1
{
public static void main (String[] args)
{
String biz = args[1];
String baz = args[2];
String rip = args[3];
System.out.println("Arg is " + rip);
}
}
run through terminal:
> javac Test1.java
> java Test1 java Myfile 1 2 2 3 4
Arg is 2.

So, option B will be right.

public class Myfile
{
public static void main (String[] args)
{
String biz = args[1];
String baz = args[2];
String rip = args[3];
System.out.println("Arg is " + rip);
}
}


See here;

Select how you would start the program to cause it to print: *Arg is 2*
We have to print *Arg is 2* and array start with *index 0*
So by option, we need 2 at the index of 3.

args[0] note it is not given in program
args[1]
args[2]
at args[3] we need 2 so by option *java Myfile 1 3 2 2* it is correct.

@All.

Here args take the value from the command line i.e command line arguments from the keyboard.

When you compile the program and runs it using java Test .
Along with java Test you have to give the value for an array also like a[0],a[1],a[2] for a[3] give the int value 2 i.e you're passing the value from keyboard to that method here args is a parameter that expects some value from the user so, java Test 1,3,2,2 will be sent from the user keyboard and store it in an array in args so the value of

a[0]=1
a[1]=3
a[2]=2
a[3]=2 remember that a[0] is already been specified.

I can't understand this. Please, anyone, help me to get this.

'java Myfile' is written to run the program after compilation and it's not an argument. Actually arguments start from 1.
args[0]=1
args[1]=3
args[2]=2
args[3]=2

So, option C is the correct answer.

I Am not understanding please explain correctly.

$javac Example.java
$java -Xmx128M -Xms16M Example
-2 -2.0
1 1.0
same results 2 time(s).

Here is a result for above question.

Thanks, @Ted.

Your explanation is very helpful to understand.

Agree @Suneel.

This will generate ArrayIndexOutOfBoundException.