Java Programming - Flow Control - Discussion
Discussion Forum : Flow Control - Finding the output (Q.No. 8)
8.
What will be the output of the program?
public class Test
{
public static void main(String [] args)
{
int I = 1;
do while ( I < 1 )
System.out.print("I is " + I);
while ( I > 1 ) ;
}
}
Answer: Option
Explanation:
There are two different looping constructs in this problem. The first is a do-while loop and the second is a while loop, nested inside the do-while. The body of the do-while is only a single statement-brackets are not needed. You are assured that the while expression will be evaluated at least once, followed by an evaluation of the do-while expression. Both expressions are false and no output is produced.
Discussion:
14 comments Page 1 of 2.
Mounika said:
4 years ago
In the definition of the block, if we don, t specify statement using block ({}), only the first statement consider. Here condition file so no output produced.
Rajat Bansal said:
9 years ago
code can be write as:
do
{
while(I>1)S.O.P("I is :"+I);
}
while(I<1);
As 1 statement ends with the encounter of; which is present at the end of the print statement that's why there is no need of braces after "do" . and both conditions are false that's why no output.
do
{
while(I>1)S.O.P("I is :"+I);
}
while(I<1);
As 1 statement ends with the encounter of; which is present at the end of the print statement that's why there is no need of braces after "do" . and both conditions are false that's why no output.
(2)
Vasanth said:
9 years ago
I Tried to run this program. Strangely this may run, Can someone explain how it works?
Ramakrishna said:
9 years ago
Answer should be option D. Compilation error due to unreachable code.
Rahul Khandare said:
10 years ago
What does int I mean?
Can we declare variable name as a capital letter?
How compiler gets this as a token?
Can we declare variable name as a capital letter?
How compiler gets this as a token?
Zoran said:
10 years ago
Obviously this is the answer :)
public static void main(String [] args)
{
int I = 5;
do //start do while
while ( I < 10 ) System.out.print("I is " + I);//one statement
while ( I > 1 ) ; //end do while
}
public static void main(String [] args)
{
int I = 5;
do //start do while
while ( I < 10 ) System.out.print("I is " + I);//one statement
while ( I > 1 ) ; //end do while
}
Raj said:
1 decade ago
do while(); semicolon is required.
Suresh said:
1 decade ago
public class Test
{
public static void main(String [] args)
{
int I = 1;
do
while ( I < 1 ){
System.out.print("I is " + I);
}
while ( I > 1 ) ;
}
}
As per my understanding above code inside do-while loop while expression is having only one statement that is reason there is no brackets required.
{
public static void main(String [] args)
{
int I = 1;
do
while ( I < 1 ){
System.out.print("I is " + I);
}
while ( I > 1 ) ;
}
}
As per my understanding above code inside do-while loop while expression is having only one statement that is reason there is no brackets required.
Simar said:
1 decade ago
From what I understand here is that expressions are not counted as statements. So technically there is only one statement i.e in the while (I < 1).
I could also add more expressions, and it would still be the same. Hope the following example helps you understand it better.
class Test
{
public static void main(String [] args)
{
int I = 1;
do for(int j = 0; j < 5; j++) while(I < 1)
System.out.print("I is " + I);
while ( I > 1 ) ;
}
}
I could also add more expressions, and it would still be the same. Hope the following example helps you understand it better.
class Test
{
public static void main(String [] args)
{
int I = 1;
do for(int j = 0; j < 5; j++) while(I < 1)
System.out.print("I is " + I);
while ( I > 1 ) ;
}
}
Austin said:
1 decade ago
The compiler will try to associate the 1st "while" encountered with the last "do" encountered.
Hence, it should give compilation error as statement missing;
Hence, it should give compilation error as statement missing;
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