Java Programming - Flow Control - Discussion

Discussion Forum : Flow Control - Finding the output (Q.No. 5)
5.
What will be the output of the program?
public class If2 
{
    static boolean b1, b2;
    public static void main(String [] args) 
    {
        int x = 0;
        if ( !b1 ) /* Line 7 */
        {
            if ( !b2 ) /* Line 9 */
            {
                b1 = true;
                x++;
                if ( 5 > 6 ) 
                {
                    x++;
                }
                if ( !b1 ) 
                    x = x + 10;
                else if ( b2 = true ) /* Line 19 */
                    x = x + 100;
                else if ( b1 | b2 ) /* Line 21 */
                    x = x + 1000;
            }
        }
        System.out.println(x);
    }
}
0
1
101
111
Answer: Option
Explanation:

As instance variables, b1 and b2 are initialized to false. The if tests on lines 7 and 9 are successful so b1 is set to true and x is incremented. The next if test to succeed is on line 19 (note that the code is not testing to see if b2 is true, it is setting b2 to be true). Since line 19 was successful, subsequent else-if's (line 21) will be skipped.

Discussion:
24 comments Page 3 of 3.

Yash maheshwari said:   10 years ago
Can any one explain it step by step?

Rani said:   7 years ago
Why not 1001? please explain it.
(1)

Vien said:   1 decade ago
Why? x must be 1001, why 101?

Sunil said:   1 decade ago
How come b2 become true ?


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