Java Programming - Flow Control - Discussion
Discussion Forum : Flow Control - Finding the output (Q.No. 5)
5.
What will be the output of the program?
public class If2
{
static boolean b1, b2;
public static void main(String [] args)
{
int x = 0;
if ( !b1 ) /* Line 7 */
{
if ( !b2 ) /* Line 9 */
{
b1 = true;
x++;
if ( 5 > 6 )
{
x++;
}
if ( !b1 )
x = x + 10;
else if ( b2 = true ) /* Line 19 */
x = x + 100;
else if ( b1 | b2 ) /* Line 21 */
x = x + 1000;
}
}
System.out.println(x);
}
}
Answer: Option
Explanation:
As instance variables, b1 and b2 are initialized to false. The if tests on lines 7 and 9 are successful so b1 is set to true and x is incremented. The next if test to succeed is on line 19 (note that the code is not testing to see if b2 is true, it is setting b2 to be true). Since line 19 was successful, subsequent else-if's (line 21) will be skipped.
Discussion:
24 comments Page 1 of 3.
Juaneco said:
3 years ago
Here b2 takes the true value.
if ( b2 = true ).
Here it is checked if b2 is true.
if ( b2 == true ).
if ( b2 = true ).
Here it is checked if b2 is true.
if ( b2 == true ).
(1)
Harshad said:
4 years ago
Consider both if ( !b1 ) /* Line 7 */ if ( !b2 ) /* Line 9 */ are true.
Then b1 = true; gets executed //line11
And x++ makes x = 1 //initially x was 0;
alright 5 > 6 is false that's not going to execute anywhere,
Control will come at line no 17...if ( !b1 ) not b1 means false we have already consider b1 is true
then b1 not going to execute.
Yes, else if ( b2 = true ) bcoz we already consider b2 is true x = x + 100; gets executed 101
if one else if executed then control will not transfer to the 2nd else if.
That's why 101 gets printed!.
Then b1 = true; gets executed //line11
And x++ makes x = 1 //initially x was 0;
alright 5 > 6 is false that's not going to execute anywhere,
Control will come at line no 17...if ( !b1 ) not b1 means false we have already consider b1 is true
then b1 not going to execute.
Yes, else if ( b2 = true ) bcoz we already consider b2 is true x = x + 100; gets executed 101
if one else if executed then control will not transfer to the 2nd else if.
That's why 101 gets printed!.
(1)
Rani said:
7 years ago
Why not 1001? please explain it.
(1)
Yami said:
9 years ago
This will compile? Explain.
"else if (b2 = true) /* Line 19 */ ".
b2 = true ?
"else if (b2 = true) /* Line 19 */ ".
b2 = true ?
(1)
Sujala said:
10 years ago
If(!b2) returns true.
It is similar to !(false).
In condition if (b2 = true) at this moment true is assigned to b2 and returns true value.
But we can't able to assign if (i = 5) //it is error.
At any instance if condition returns either true or false only.
So the statements.
x = x+100; //x = 1+100.
x = 101 is the right answer.
It is similar to !(false).
In condition if (b2 = true) at this moment true is assigned to b2 and returns true value.
But we can't able to assign if (i = 5) //it is error.
At any instance if condition returns either true or false only.
So the statements.
x = x+100; //x = 1+100.
x = 101 is the right answer.
(1)
Udesha said:
10 years ago
What is the meaning of "if (!b1)"? What does it do?
Don't we have to use a condition inside those parentheses of the if condition?
Don't we have to use a condition inside those parentheses of the if condition?
Arun said:
9 years ago
In this statement, if(b2=true) first assign b2 value as true then check condition.
Kishan said:
9 years ago
x must be 1001, assignment is not allowed inside an if statement in Java .
Geeta said:
9 years ago
A question is wrong. Kindly correct it at.
X = x + 1000.
X = x + 1000.
Divesh Singla said:
10 years ago
if ( 5 > 6 )
{
x++;
}
if ( !b1 )
x = x + 10;
Why this part is not considered?
{
x++;
}
if ( !b1 )
x = x + 10;
Why this part is not considered?
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