Java Programming - Flow Control - Discussion

public class Switch2
{
final static short x = 2;
public static final int y = 0;
public static void main(String [] args)
{
for (int z=0; z < 3; z++)
{
switch (z)
{
case y: System.out.print("0 "); /* Line 11 */
case x-1: System.out.print("1 "); /* Line 12 */
case x: System.out.print("2 "); /* Line 13 */
}
}
}
}

// Can you tell me why the above program giving 012122 as output?

public class Main
{
final static short x = 2;
final static int y = 0;
public static void main(String [] args)
{
for (int z=0; z < 3; z++)
{
switch (z)
{
case y: System.out.print("0 "); /* Line 11 */
case x-1: System.out.print("1 "); /* Line 12 */
case x: System.out.print("2 "); /* Line 13 */
}
}
}
}

Here, if we change the static to final then the output : 012122.

@Mahesh:

In your program output will be:

1st time (at z=0) condition (case y) : 012 (because No break).

2nd time (at z=1) condition (x-1) : 12 (again after 1 No break, so 2 printed).

3rd time (at z=2) condition (x=2) : 2.

So output : 012122.

Here x is evaluated at compile time as x is a final variable but y is not a final variable so compiler evaluates y's value at runtime. So the value of is not considered as constant.

Nevermind i got the logic. I forgot when we define x and y as static final. They become constant. So inside switch case - case y will mean case 0 and so on for others.

I declare why as final and not remove final so my program is success.

Its mean switch case acceptable public.

In C/C++ int values are work well. But why in Java int values does not work? Please help anyone.

Why no error in line 13? I learnt type of case label should be same as 'x' (switch (x) ).

Why is y, (a public variable) not acceptable in a switch case? Thanks in Advance.

When I define the keyword public for why it display the op as 012122 how is it?