Java Programming - Flow Control - Discussion

Discussion Forum : Flow Control - General Questions (Q.No. 3)
3.
public void test(int x) 
{ 
    int odd = 1; 
    if(odd) /* Line 4 */
    {
        System.out.println("odd"); 
    } 
    else 
    {
        System.out.println("even"); 
    } 
}
Which statement is true?
Compilation fails.
"odd" will always be output.
"even" will always be output.
"odd" will be output for odd values of x, and "even" for even values.
Answer: Option
Explanation:

The compiler will complain because of incompatible types (line 4), the if expects a boolean but it gets an integer.

Discussion:
15 comments Page 2 of 2.

Shantanu said:   1 decade ago
What when we use while (1)?

That time it gives exact output in c++. It is not allowed in java.

Bandana said:   1 decade ago
In line 4. There is no Boolean condition. It just an integer. That's why it is compile error.

Sajib said:   8 years ago
How it becomes compilation error? 0 if false otherwise true.
(2)

Surendra said:   9 years ago
With in if condition boolean expression is given.
(1)

Bharathraj said:   1 decade ago
How it is a compile error?
(1)


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