Java Programming - Flow Control - Discussion

Discussion Forum : Flow Control - General Questions (Q.No. 3)
3.
public void test(int x) 
{ 
    int odd = 1; 
    if(odd) /* Line 4 */
    {
        System.out.println("odd"); 
    } 
    else 
    {
        System.out.println("even"); 
    } 
}
Which statement is true?
Compilation fails.
"odd" will always be output.
"even" will always be output.
"odd" will be output for odd values of x, and "even" for even values.
Answer: Option
Explanation:

The compiler will complain because of incompatible types (line 4), the if expects a boolean but it gets an integer.

Discussion:
15 comments Page 1 of 2.

Vikash rai said:   6 years ago
Integer can not behave like boolean. And there is not a complete condition statement in if condition.

So it will throw compilation error.

Thanks.

Sajib said:   8 years ago
How it becomes compilation error? 0 if false otherwise true.
(2)

Surendra said:   9 years ago
With in if condition boolean expression is given.
(1)

Shrek said:   9 years ago
As far as I have learned, any number other than 0 in the if condition results in a true result. 0 returns false and hence in this case if should actually return true and print ODD.

Although, I am not sure if this is invalid incase of java.
(1)

Shantanu said:   1 decade ago
What when we use while (1)?

That time it gives exact output in c++. It is not allowed in java.

Anjan Chandra Das said:   1 decade ago
In java the condition parameters are "true" and "false" i.e. in Boolean format.

But in C or C++ the positive integers are taken as true like.

If (500) // is taken as true in C language. So, Don't be confuse the feature of java and C.
(1)

Nashath Nasar said:   1 decade ago
Hi guys,

Option A is the correct answer, because there should be a Boolean expression within the brackets followed by "if". Here is an integer number (Odd) within the brackets. That's why it's compile error.
(1)

Bandana said:   1 decade ago
In line 4. There is no Boolean condition. It just an integer. That's why it is compile error.

Bharathraj said:   1 decade ago
How it is a compile error?
(1)

Surajit said:   1 decade ago
In C programming language while(1){} is a infinite loop. But in java while(1){} is a compilation error because in condition it expects either true of false(both keyword). So, the same c program equivalent code in java is while(true){} which represents infinite loop.
(1)


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