Java Programming - Flow Control - Discussion
Discussion Forum : Flow Control - General Questions (Q.No. 3)
3.
public void test(int x)
{
int odd = 1;
if(odd) /* Line 4 */
{
System.out.println("odd");
}
else
{
System.out.println("even");
}
}
Answer: Option
Explanation:
The compiler will complain because of incompatible types (line 4), the if expects a boolean but it gets an integer.
Discussion:
15 comments Page 2 of 2.
Prashant said:
1 decade ago
Here if (odd) expects value of odd variable.
As declared earlier value of odd is 1 then condition holds true. Odd should be printed. Didn't understand why it is compiler error.
As declared earlier value of odd is 1 then condition holds true. Odd should be printed. Didn't understand why it is compiler error.
Manoj said:
1 decade ago
Here if (odd) expects value of odd variable.
As declared earlier value of odd is 1 then condition holds true. Odd should be printed. Didn't understand why it is compiler error.
As declared earlier value of odd is 1 then condition holds true. Odd should be printed. Didn't understand why it is compiler error.
Bandana said:
1 decade ago
In line 4. There is no Boolean condition. It just an integer. That's why it is compile error.
Shantanu said:
1 decade ago
What when we use while (1)?
That time it gives exact output in c++. It is not allowed in java.
That time it gives exact output in c++. It is not allowed in java.
Vikash rai said:
6 years ago
Integer can not behave like boolean. And there is not a complete condition statement in if condition.
So it will throw compilation error.
Thanks.
So it will throw compilation error.
Thanks.
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