Java Programming - Exceptions - Discussion
public class ExceptionTest
{
class TestException extends Exception {}
public void runTest() throws TestException {}
public void test() /* Point X */
{
runTest();
}
}
Option B is correct. This works because it DOES throw an exception if an error occurs.
Option A is wrong. If you compile the code as given the compiler will complain:
"unreported exception must be caught or declared to be thrown" The class extends Exception so we are forced to test for exceptions.
Option C is wrong. The catch statement belongs in a method body not a method specification.
Option D is wrong. TestException is a subclass of Exception therefore the test method, in this example, must throw TestException or some other class further up the Exception tree. Throwing RuntimeException is just not on as this belongs in the java.lang.RuntimeException branch (it is not a superclass of TestException). The compiler complains with the same error as in A above.
Because the runTest() throws an TestException it is subclass of Exception so when we call runTest() in any method that method /*(In which method we calling runTest())*/ also caught either TestException or Exception.
For compilation the compiler doesn't check for main method Run time only JVM checks for main method. So it is successfully compiled but not executed.
either surround the calling method with try-catch block or throws exception.