public class RTExcept
{
public static void throwit ()
{
System.out.print("throwit ");
throw new RuntimeException();
}
public static void main(String [] args)
{
try
{
System.out.print("hello ");
throwit();
}
catch (Exception re )
{
System.out.print("caught ");
}
finally
{
System.out.print("finally ");
}
System.out.println("after ");
}
}
[A].
hello throwit caught
[B].
Compilation fails
[C].
hello throwit RuntimeException caught after
[D].
hello throwit caught finally after
Answer: Option D
Explanation:
The main() method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal.
A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.
Since RuntimeException is not a subclass of Exception class and neither it needs to be declared or handle then how can a catch clause with Exception object as argument can handle this Runtime Exception?
Azam said:
(Mar 31, 2014)
Sorry, but RuntimeException class is the Parent class of Exception class. So it can be handled by exception class.
Anurag Singh said:
(Oct 2, 2014)
Hi, Exception class is parent class of RunTimeException.
Prasad said:
(Feb 24, 2015)
I have a question on above code. I think the static method need to be execute first.
Sree said:
(Aug 6, 2015)
If we have normal static method and public static void main() method, First preference is given to static main method.
Wojtek said:
(Sep 16, 2015)
Why we do not need to statement 'throws' RuntTimeEx?
Seonab said:
(Mar 8, 2017)
Class is the Parent class of Exception class.
Seonab said:
(Mar 8, 2017)
I have a question on above code. I think the static method need to be execute first.
Nikshitha said:
(Sep 16, 2018)
But after finally block, if any statement exists does it executes?
As per my knowledge, I think it should not execute.
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