Java Programming - Declarations and Access Control - Discussion
Discussion Forum : Declarations and Access Control - Pointing out the correct statements (Q.No. 5)
5.
class A
{
A( ) { }
}
class B extends A
{ }
Answer: Option
Explanation:
Option B is correct. Class B inherits Class A's constructor which has no arguments.
Option A is wrong. Class B inherits Class A's constructor which uses default access.
Option C is wrong. There is just no implicit call to this( ).
Discussion:
11 comments Page 1 of 2.
Vandit said:
3 years ago
@All.
Constructors are not members, so they are not inherited by subclasses, but the constructor of the superclass can be invoked from the subclass.
Constructors are not members, so they are not inherited by subclasses, but the constructor of the superclass can be invoked from the subclass.
Nikhil said:
8 years ago
One constructor cannot inherit another constructor in any case.
Dablu Gupta said:
1 decade ago
Can anyone please explain about initialization of a float object.
Meaning of these two lines:.
Float f1[ ], f2[ ];
F1 = new float[10];
Meaning of these two lines:.
Float f1[ ], f2[ ];
F1 = new float[10];
Dablu Gupta said:
1 decade ago
Can anyone please explain about initialization of a float object.
Syed Shahzad said:
1 decade ago
public class A {
A() {
System.out.println("A");
}
}
public class B extends A{
}
1. Class B if in the same package as of A.
2. Class B constructor default access is public.
3. Class B constructor will make call class A default constructor, here class A has explicit constructor declared with default access so it will be executed as a first thing in constructor B.
4. According to me option is correct at all.
A() {
System.out.println("A");
}
}
public class B extends A{
}
1. Class B if in the same package as of A.
2. Class B constructor default access is public.
3. Class B constructor will make call class A default constructor, here class A has explicit constructor declared with default access so it will be executed as a first thing in constructor B.
4. According to me option is correct at all.
Inayath said:
1 decade ago
If we are not providing any constructor compiler will place a default(no arg constructor) and call to it's super class constructor.
Compiler provide following code for B class as follows.
class B extends A{
B(){
super();
}
}
So constructors are not inherited although they are chained.
Compiler provide following code for B class as follows.
class B extends A{
B(){
super();
}
}
So constructors are not inherited although they are chained.
Ejunika said:
1 decade ago
class A
{
A( ) { }
}
class B extends A
{ }
Can any one tell me that B's constructor is public or not?
{
A( ) { }
}
class B extends A
{ }
Can any one tell me that B's constructor is public or not?
Rakesh said:
1 decade ago
There is implicit call to base class constructor from each derived class constructor . Using keyword super() it calls base class constructor . "super();" is first statement of every derived class constructor either we provide explicitly or it is provided by JVM implicitly.
Ashok said:
1 decade ago
Then how the super class constructor will be executed when we create the object for sub class.
Aditya said:
1 decade ago
constructors are NOT inherited in subclass....
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