Java Programming - Declarations and Access Control - Discussion

Discussion Forum : Declarations and Access Control - Finding the output (Q.No. 3)
3.
What will be the output of the program?
public class A
{ 
    void A() /* Line 3 */
    {
        System.out.println("Class A"); 
    } 
    public static void main(String[] args) 
    { 
        new A(); 
    } 
}
Class A
Compilation fails.
An exception is thrown at line 3.
The code executes with no output.
Answer: Option
Explanation:

Option D is correct. The specification at line 3 is for a method and not a constructor and this method is never called therefore there is no output. The constructor that is called is the default constructor.

Discussion:
15 comments Page 2 of 2.

Dilly said:   1 decade ago
Unlike C++ in Java we can have method name same as of class name.

But like C++ constructor doesn't have return type not even void.

Mahi said:   1 decade ago
class a
{
void a(){}
}
a()
{}
}

is both of the methods are constructor of class a, if not why?

Sandeep Tomar said:   1 decade ago
If we are allowed to have method with same name. How Compiler will come to know whether we have written a valid function code or a wrong constructor code. Please help to clarify on this. Thanks.

Aqueenni said:   10 years ago
As per my knowledge, method name starts with a lowercase.

Here it is void A().

So one can also think that it is a constructor declared wrongly and hence the option B. Compilation fails.

Ishu said:   9 years ago
Constructor don't have return type and in this problem there is return type which is void A() so this is a method and int his very question method name is also with same name as class so block will not execute.


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