Java Programming - Declarations and Access Control - Discussion
Discussion Forum : Declarations and Access Control - General Questions (Q.No. 8)
8.
Which cause a compiler error?
Answer: Option
Explanation:
Option B generates a compiler error: <identifier> expected. The compiler thinks you are trying to create two arrays because there are two array initialisers to the right of the equals, whereas your intention was to create one 3 x 3 two-dimensional array.
To correct the problem and make option B compile you need to add an extra pair of curly brackets:
int [ ] [ ] scores = { {2,7,6}, {9,3,45} };
Discussion:
10 comments Page 1 of 1.
Rajan said:
1 decade ago
If your program is compiled successfully without errors then its ok and no compile time error is there. If it gives error when you compile it means the errors are compile time errors.
If your program is compiled successfully without errors but causes some exception during running it means its a run time error.
If your program is compiled successfully without errors but causes some exception during running it means its a run time error.
Saba said:
8 years ago
In the last option it follows like this:
results[0]=new integer(3)
results[1]=new integer(5)
results[2]=new integer(8)
That is each and every element of results[] is also a single dimensional array and as all the elements of result array are even integers hence there will be no error.
Hope you understand.
results[0]=new integer(3)
results[1]=new integer(5)
results[2]=new integer(8)
That is each and every element of results[] is also a single dimensional array and as all the elements of result array are even integers hence there will be no error.
Hope you understand.
RF Fan said:
1 decade ago
@Vinodhini .
Its allocating memory (of course through object creation). And We all know int a[]=new int[2] can be used its nothing but we are allocating an array of values to a (here its 2) then there aint no problem in writing Boolean the same.
boolean a[]= new boolean[2];
Its allocating memory (of course through object creation). And We all know int a[]=new int[2] can be used its nothing but we are allocating an array of values to a (here its 2) then there aint no problem in writing Boolean the same.
boolean a[]= new boolean[2];
LeitrimDroid said:
1 decade ago
Hi Yatendra,
I believe it puts three boolean values in a new array called results, such that
results[0] = true.
results[1] = false.
results[2] = true.
I believe it puts three boolean values in a new array called results, such that
results[0] = true.
results[1] = false.
results[2] = true.
Vinodhini said:
1 decade ago
But boolean is just a keyword. So how can we create an object for a keyword! If you say boolean is a wrapper class it should be Boolean and not boolean!
Riya said:
1 decade ago
Integer results[ ] = {new Integer(3), new Integer(5), new Integer(8)};
How it allocates memory to the variable results?
How it allocates memory to the variable results?
Yatendra singh chauhan said:
1 decade ago
boolean results[ ] = new boolean [] {true, false, true};
What is the meaning of this line?
What exactly it perform?
What is the meaning of this line?
What exactly it perform?
Akash said:
1 decade ago
How we can find the error is compile time or run time?
Cheenu said:
9 years ago
Please explain how last option is correct?
Saurabh gupta said:
8 years ago
I too think the last option is wrong.
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