General Knowledge - Physics - Discussion

Discussion Forum : Physics - Section 1 (Q.No. 23)
23.
Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
0.14 m/s
140 m/s
1.4 km/s
14 m/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
46 comments Page 4 of 5.

Ihsan ullah said:   9 years ago
Thanks to everyone. Really helpful explanation.

Sanjay said:   1 decade ago
Can I know how this formula has been derived?

Tamanna said:   1 decade ago
Can you please explain how this formula came?

Nuclei said:   7 years ago
It is based on the Newton 2nd law of Motion.
(1)

Nikhil said:   1 decade ago
As the S.I unit of acceleration is m/s.

Mukuuuuu champ physics said:   1 decade ago
tan$=v2/rg
tan$=miu
sqrtrgmiu=velocity

Akin said:   1 decade ago
Please which law states this @Bhiva?
(1)

Jasbir Ranga said:   8 years ago
Yes, I agree @Sayyad Touffiq Ali.

Joshi said:   1 decade ago
v=mu*r*g is the correct formula.

Ahmad said:   9 years ago
Can a car move without friction?


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