General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 23)
23.
Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
Discussion:
46 comments Page 3 of 5.
Ashish said:
6 years ago
mv^2/r = u(friction)mg.
By using above formula "v" can be calculated.
By using above formula "v" can be calculated.
(2)
Pablo said:
1 decade ago
But max speed can be 140m/sec. Because even it will result in the overturn.
Amit bole said:
1 decade ago
But the distance covered by the car is the circumference of a circle.
Vvn reddy said:
8 years ago
.2*100*9.8=196.
Root applied by 196=14 so the answer is 14.
Root applied by 196=14 so the answer is 14.
(2)
Antim said:
9 years ago
Centrifugal force = Friction force,
mv^2/r = friction * mg.
mv^2/r = friction * mg.
Supreeth said:
1 decade ago
mv2/r = μmg.
v2/100 = 0.2*9.8.
v2 = 196.
v = 14 m/s.
v2/100 = 0.2*9.8.
v2 = 196.
v = 14 m/s.
Gerald said:
1 decade ago
Can someone who knows this make it clear to us please.
Bhavy said:
1 decade ago
9.8 comes from the g, which is gravitational constant.
Josephine said:
9 years ago
Thanks for all your good work. It is really helpful.
Kailas said:
9 years ago
Thanks to everyone. Really helpful explanation.
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