General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 79)
79.
An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
Discussion:
36 comments Page 2 of 4.
Shekhar verma said:
1 decade ago
Velocity:600*5/18 m./sec.=500/3m./sec. Hy=Uy*t+1/2g*t*t : 1960=0+ 1/2*9.8*t*t therefore t=20 sec. So Range AB=v*t=500/3*20 m.=10/3 km.=3.33 km.
Tushar said:
1 decade ago
When a body is projected into space and no longer propelled by fuel and other external forces except gravity it's motion is called a projectile motion.
Shanu said:
3 years ago
They haven't mentioned the time.
Then how did you guys calculate the projectile motion? Please explain me.
Then how did you guys calculate the projectile motion? Please explain me.
Maloni said:
8 years ago
@Vinod.
May I know why didn't you put the value of acceleration while using 2nd law of motion equation.
May I know why didn't you put the value of acceleration while using 2nd law of motion equation.
Latha said:
9 years ago
@Tms.
Projectile motion means a particle moves along curved path due to gravity and formula is 1/2gt^2.
Projectile motion means a particle moves along curved path due to gravity and formula is 1/2gt^2.
Ambisa mekonen said:
9 years ago
The required distance from A to B is equal to range AB?
Please clarify it.
Please clarify it.
Linda said:
1 decade ago
Actually what is this question talking about when the time is not given.
Rajat shukla said:
10 years ago
Why is initial velocity 0? Why not 600 as plane is moving at 600?
Shanaya said:
9 years ago
How to find out the angle that bomb is making with vertical?
Navin chahar said:
1 decade ago
What is projectile motion and not sure about this question?
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