General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 60)
60.
ML2T-2 is the dimensional formula for
Discussion:
14 comments Page 2 of 2.
Arafath said:
9 years ago
How a=L/T2?
Prathap said:
8 years ago
T = f.d.
Then T = ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
Then T = ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
Rustam xaman said:
8 years ago
t=f.d f=ma m=M and d=L.
= M(a=v/t).L where v= s/t s=L
=M(L/t2).L WHERE t2 go square
=ML2T-2.
= M(a=v/t).L where v= s/t s=L
=M(L/t2).L WHERE t2 go square
=ML2T-2.
Ashish said:
6 years ago
Couple acting on body, unit is N-mm.
N = kg.mm.s^-2.
N-mm = kg.mm^2.s^-2.
N-mm = ML^2T^-2.
N = kg.mm.s^-2.
N-mm = kg.mm^2.s^-2.
N-mm = ML^2T^-2.
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