General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 60)
60.
ML2T-2 is the dimensional formula for
Discussion:
14 comments Page 1 of 2.
Ashish said:
6 years ago
Couple acting on body, unit is N-mm.
N = kg.mm.s^-2.
N-mm = kg.mm^2.s^-2.
N-mm = ML^2T^-2.
N = kg.mm.s^-2.
N-mm = kg.mm^2.s^-2.
N-mm = ML^2T^-2.
Rustam xaman said:
8 years ago
t=f.d f=ma m=M and d=L.
= M(a=v/t).L where v= s/t s=L
=M(L/t2).L WHERE t2 go square
=ML2T-2.
= M(a=v/t).L where v= s/t s=L
=M(L/t2).L WHERE t2 go square
=ML2T-2.
Prathap said:
8 years ago
T = f.d.
Then T = ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
Then T = ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
Arafath said:
9 years ago
How a=L/T2?
Venkatraj.A said:
1 decade ago
T = f.d.
Then T = ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
= ML2T-2.Formula for Couple acting on body (T)=F*d.
= Ma*d [F=M*a].
= M*dv/t*d [a==(vf-vi)/t)].
= M*(d/t/t)*d.
= Md^2/t^2.
= ML^2T^-2.
Then T = ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
= ML2T-2.Formula for Couple acting on body (T)=F*d.
= Ma*d [F=M*a].
= M*dv/t*d [a==(vf-vi)/t)].
= M*(d/t/t)*d.
= Md^2/t^2.
= ML^2T^-2.
BALIRAM said:
1 decade ago
Two equal and opposite parallel forces acting along different lines on a body constitute a couple.
The product of force and perpendicular distance between two force.
So force*distance = couple of force.
UNIT: NEWTON*METER = MLT^-2 L = ML^2T^-2.
The product of force and perpendicular distance between two force.
So force*distance = couple of force.
UNIT: NEWTON*METER = MLT^-2 L = ML^2T^-2.
Sujit said:
1 decade ago
COUPLE ACTING ON BODY MEANS TORQUE. SO USING THE FORMULA:
T = f.d.
THEN T= ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
= ML2T-2.
T = f.d.
THEN T= ma.d.
= M.L/T2.L (a=L/T2) & (d=L).
= ML2/T2.
= ML2T-2.
Siddarrh said:
1 decade ago
Work and couple are two different things work helps us to move an object moment or couple indicates the possibilities for the work to be done.
NITSH KUMAR said:
1 decade ago
Force*distance between the force = Work.
Debjyoti Bandyopadhyay said:
1 decade ago
Couple = Force*distance between the force = Work.
Dimension of Work is ML^2T^-2.
Dimension of Work is ML^2T^-2.
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