General Knowledge - Physics - Discussion

Discussion Forum : Physics - Section 1 (Q.No. 16)
16.
If two bodies of different masses, initially at rest, are acted upon by the same force for the same time, then the both bodies acquire the same
velocity
momentum
acceleration
kinetic energy
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
26 comments Page 3 of 3.

Rija Ali said:   1 decade ago
In this case momentum=m*v

Here v is 0 so if mass m1 is 3 and m2 is 4 but v is 0.

So momentum remains constant.

Mark said:   1 decade ago
Second law of motion by newton will greatly explained it.

Mohib said:   1 decade ago
If the ans is not velocity then definitly not option B.

Because P=mv. if v changes then how can p same in both cases.

Assume case 1;
m=1kg v=1m\s then p=1kgm\s

Assume case 2;
m=2kg v=2m\s then p=4kgm\s.

All options are not satisfactory.

Subhasish sahoo said:   1 decade ago
Force=rate of change of momentum.

As force & time both are constant. So we get momentum=constant.

Susant said:   1 decade ago
momentum = force* time

RAJAL said:   1 decade ago
1)According to newton,s 2nd law force = rate of change of momentum i.e.,momentum=m*v

F= M*(D*V/DT)=M*A

so it is case of m1v1 and m2v2

m1 is not = m2

hence v1 is not = v2

now Newton's 3rd law come in pictutre during impact

F1=F2 ......(equal and opposite reaction)

hence m1a1=m2a2

momentum1=momentum2

2)

it can be a case of special relativity

increase in velocity= increase in inertia = increase in enrgy

then apply law of conservation of energy again newtons 3rd law

3)

concider it is case of closed system between two bodies

u get the answer


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