General Knowledge - Physics - Discussion

F= ma.
Therefore a=F/m.

F is same in both cases but m is different therefore they can not have same acc.

Suppose,

Min first case be 2 and second case b 4. And force is 10 then in first case acc = 5 whereas in second case it is = 5/2. Which is not equal.

Now ke = 1/2 mv(square).
V = under root of ( 2 ke /m ).

Case 1 : m is 2 and ke is 10.
V =underfoot of (2*10/2)= underfoot 10.

Case 2 : M = 4 ke = 10

V = underfoot of (2*10/4) = under root of 5. Which is again not equal.
Then. V = ut + (1/2) at square in this case acc is changing again as v proved above therefore. It's not correct option.

And

Momentum.

P = f*t therefore both r constancent in ques. Therefore momentum is the answer.

1)According to newton,s 2nd law force = rate of change of momentum i.e.,momentum=m*v

F= M*(D*V/DT)=M*A.
so it is case of m1v1 and m2v2.
m1 is not = m2.
hence v1 is not = v2.
now Newton's 3rd law come in pictutre during impact.
F1=F2 ......(equal and opposite reaction).
Hence m1a1=m2a2.
Momentum1=momentum2.

2) It can be a case of special relativity

Increase in velocity= increase in inertia = increase in energy
Then apply law of conservation of energy again newtons 3rd law.

3) Consider it is case of closed system between two bodies,

You will get the answer.

1)According to newton,s 2nd law force = rate of change of momentum i.e.,momentum=m*v

F= M*(D*V/DT)=M*A

so it is case of m1v1 and m2v2

m1 is not = m2

hence v1 is not = v2

now Newton's 3rd law come in pictutre during impact

F1=F2 ......(equal and opposite reaction)

hence m1a1=m2a2

momentum1=momentum2

2)

it can be a case of special relativity

increase in velocity= increase in inertia = increase in enrgy

then apply law of conservation of energy again newtons 3rd law

3)

concider it is case of closed system between two bodies

u get the answer

The answer is absolutely acceleration. You know that F = ma/mg.

Let consider the two masses under gravity influence, since they are under the same F of gravity they will have the same acceleration because all objects if drop at the same time, they would all get to the ground at the same time neglecting air resistance. Equal or unequal masses will have different acceleration on the surface of the Earth. But the question does not signify whether the object is on earth or in space.

We know that momentum = mass*velocity.

Even if we suppose that both acquire same velocity,

Then also the answer is not true as both have different masses.

Also among the given options, velocity is the only quantity which does not depend on mass and else other quantities do depend on mass.

k.e. = 1/2*mass*velocity square.

p = m*v.

Acceleration = force/mass.

So as a conclusion velocity should remain constant.

Impulse and linear momentum have the same value.

Impulse = force * time = (mass * acceleration) * time = mass * (acceleration * time) = mass * velocity.

In question equal forces are applied for the same time, so two bodies have the same impulse means the same momentum.

Dear students, I did it through 1 hour of r & d by a simple method.

I think practically if force is same for both body so more mass body has less velocity than low mass body.

But momentum is product of mass and velocity. Hence more mass has less velocity and low mass has more velocity, so momentum has same for both body.

If the ans is not velocity then definitly not option B.

Because P=mv. if v changes then how can p same in both cases.

Assume case 1;
m=1kg v=1m\s then p=1kgm\s

Assume case 2;
m=2kg v=2m\s then p=4kgm\s.

All options are not satisfactory.

Momentum is the right answer.

We know f = ma.

Here initial velocity u is 0.

Therefore p = f*t [ma*t = m*v-0/t*t = mv].

As force and time is constant both have same momentum.

According to newtons second law force is rate of change of momentum with time. So F=dp/dt.
We can write,
dp=f.dt.

So same force act for same time.
Hence momentum is same.