General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 28)
28.
The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature is
Discussion:
17 comments Page 2 of 2.
Nipu kalita said:
7 years ago
1mole H2O =18g =18ml = 6.023 * 10^23,
=>.0018ml =6.023 * 10^23 * 18/.0018,
=6.023 * 10^19.
=>.0018ml =6.023 * 10^23 * 18/.0018,
=6.023 * 10^19.
Abhijeet said:
1 decade ago
Why should taken (6.02 x 10exp19 molecules) molecule, if Avogadro.No is 6.023 x 1023?
Can you explain?
Can you explain?
Alok Paramanik said:
4 years ago
18ml of H2O = 6.023 * 10^23 molecules.
0.0018ml of H20 = 6.023 * 10^23 * 0.0018/18,
= 6.023 * 10^19.
0.0018ml of H20 = 6.023 * 10^23 * 0.0018/18,
= 6.023 * 10^19.
(1)
Cokol said:
7 years ago
It is because 1 mole of water is equal to the Avagadro number which is 6.023*10^19.
(1)
Ranjeet Yadav said:
1 decade ago
Number of mole = Molecule.wt*Avogadros no. Thus by multiplying both we get answer.
Vincent said:
8 years ago
How do you get 18 out of .0018?
Please clear my doubt.
Please clear my doubt.
Siv said:
3 years ago
Good explanations. Thanks, everyone.
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