General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 28)
28.
The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature is
Discussion:
17 comments Page 2 of 2.
Siva Rama Krishna said:
8 years ago
1 mole of water contains an avagadro number(6.023*10^23) of molecules.1 mole of H2O mass is 18g or volume 18ml.
So 0.0018ml of water contains 6.o23*10^19 molecules.
So 0.0018ml of water contains 6.o23*10^19 molecules.
Cokol said:
7 years ago
It is because 1 mole of water is equal to the Avagadro number which is 6.023*10^19.
(1)
Nipu kalita said:
7 years ago
1mole H2O =18g =18ml = 6.023 * 10^23,
=>.0018ml =6.023 * 10^23 * 18/.0018,
=6.023 * 10^19.
=>.0018ml =6.023 * 10^23 * 18/.0018,
=6.023 * 10^19.
Lipu said:
6 years ago
Here mentioned room temperature and at STP the volume of a gas is 22.4L = 22400ml.
So, I think the correct answer is 4.83 * 10^16.
So, I think the correct answer is 4.83 * 10^16.
(2)
Alok Paramanik said:
4 years ago
18ml of H2O = 6.023 * 10^23 molecules.
0.0018ml of H20 = 6.023 * 10^23 * 0.0018/18,
= 6.023 * 10^19.
0.0018ml of H20 = 6.023 * 10^23 * 0.0018/18,
= 6.023 * 10^19.
(1)
DebashisD said:
3 years ago
18 ml H2O.
no of molecule= 6.023x 10^19.
0.0018 ml of H2O.
No of molecule= (6.023x 10^19x0.00180/18= 6.023x10^19.
no of molecule= 6.023x 10^19.
0.0018 ml of H2O.
No of molecule= (6.023x 10^19x0.00180/18= 6.023x10^19.
Siv said:
3 years ago
Good explanations. Thanks, everyone.
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