General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 59)
59.
The maximum number of isomers for an alkene with molecular formula C4H8 is
Discussion:
25 comments Page 3 of 3.
Jimmy said:
1 decade ago
Not forget C is and trans form of CH3-CH = CH-CH3. Hence it have total 4 isomer.
Jimmy said:
1 decade ago
1) CH2 = CH-CH2-CH3.
2) CH3-CH = CH-CH3.
3) C IS FORM,
&
4) Transform of CH2 = C(CH3)2.
2) CH3-CH = CH-CH3.
3) C IS FORM,
&
4) Transform of CH2 = C(CH3)2.
Nagendra said:
1 decade ago
CH2 = CH-CH2-CH3.
CH3-CH = CH-CH3.
CH2 = C(CH3)2.
So answer is D.
CH3-CH = CH-CH3.
CH2 = C(CH3)2.
So answer is D.
HARIS said:
1 decade ago
CH2=CH-CH2-CH3
CH3-CH=CH-CH3
CH2=C(CH3)2
CH3-CH=CH-CH3
CH2=C(CH3)2
Babasaheb said:
1 decade ago
1)1-Butene,2)2-Methyl propene, 3)Cis- 2-Butene & 4)Trans 2-Butene
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