General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 16)
16.
The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is
Discussion:
27 comments Page 3 of 3.
Mehulkumar said:
1 decade ago
P4+5O2 ->P4O10
124+5(16)=204
124gm Of P4 produce 204 gram P4O10
So,
1.33gm P4 produce (204/124)*1.33=2.18gm
So close answer is 2.04gm Option (A)
124+5(16)=204
124gm Of P4 produce 204 gram P4O10
So,
1.33gm P4 produce (204/124)*1.33=2.18gm
So close answer is 2.04gm Option (A)
Prashant bhanuadsji chouke said:
1 decade ago
I understand that very well expalined.
Dinesh maurya said:
1 decade ago
Please explain in detail.
Vikram said:
1 decade ago
Balance chemical equation
P4 + 5 O2 -> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
124g of P4 produce P4O10 = 284g
So, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g
P4 + 5 O2 -> P4O10
1 mol 5 mol 1 mol
124g 160g 284g
Here limiting reagent is P4.
124g of P4 produce P4O10 = 284g
So, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g
(1)
Prashant said:
1 decade ago
I can't understand this question. Please clear this question.
(1)
Cindy said:
1 decade ago
Not clear! How?
(1)
Aruna said:
1 decade ago
Not clear please explain answer this question.
(1)
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