General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 16)
16.
The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is
Discussion:
27 comments Page 2 of 3.
Nibedita said:
7 years ago
The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete.
Jahan said:
10 years ago
P4 + 5O2 = P4O10.
128 160 288.
128 g P4 produces 288g P4O10.
1.33 g P4 "(288/128)*1.33.
= 2.99 g~3.05 g.
128 160 288.
128 g P4 produces 288g P4O10.
1.33 g P4 "(288/128)*1.33.
= 2.99 g~3.05 g.
Shiva said:
7 years ago
Why We using p-value (1.33) only in this calculation?
Why not using o value (5.07)?
Please explain me.
Why not using o value (5.07)?
Please explain me.
Jatin said:
9 years ago
Quick formula. 1.33+5.07 = 6.4.
They combined producing another element. s6.4/2 = 3.2~3.05.
They combined producing another element. s6.4/2 = 3.2~3.05.
Prashant said:
1 decade ago
I can't understand this question. Please clear this question.
(1)
Ayushi said:
9 years ago
Please explain the easy way to solve the solution.
Aditya sharma said:
7 years ago
I can't understand. Please explain the answer.
(3)
Aruna said:
1 decade ago
Not clear please explain answer this question.
(1)
Joshua Benjamin bawa said:
8 years ago
What is a limiting agent please explain?
Saroj said:
4 years ago
Thanks for the good explanation @Rajesh.
(3)
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