General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 16)
16.
The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is
Discussion:
27 comments Page 2 of 3.
Jagath said:
7 years ago
Thanks for explaining.
Shiva said:
7 years ago
Why We using p-value (1.33) only in this calculation?
Why not using o value (5.07)?
Please explain me.
Why not using o value (5.07)?
Please explain me.
Nibedita said:
7 years ago
The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete.
Ajanaku opemipo said:
8 years ago
It is 3.05.
Noor said:
8 years ago
The limiting reagent (or limiting reactant) in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.
Dinesh maurya said:
1 decade ago
Please explain in detail.
Prashant bhanuadsji chouke said:
1 decade ago
I understand that very well expalined.
Mehulkumar said:
1 decade ago
P4+5O2 ->P4O10
124+5(16)=204
124gm Of P4 produce 204 gram P4O10
So,
1.33gm P4 produce (204/124)*1.33=2.18gm
So close answer is 2.04gm Option (A)
124+5(16)=204
124gm Of P4 produce 204 gram P4O10
So,
1.33gm P4 produce (204/124)*1.33=2.18gm
So close answer is 2.04gm Option (A)
Ram said:
9 years ago
What is a limiting reagent?
Jatin said:
9 years ago
Quick formula. 1.33+5.07 = 6.4.
They combined producing another element. s6.4/2 = 3.2~3.05.
They combined producing another element. s6.4/2 = 3.2~3.05.
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