General Knowledge - Basic General Knowledge - Discussion
Discussion Forum : Basic General Knowledge - Section 2 (Q.No. 22)
22.
If speed of rotation of the earth increases, weight of the body
Discussion:
36 comments Page 2 of 4.
Happy said:
1 decade ago
As we all know energy(E)=1/2MV^2 and weight=Mg
So from the first equation we can get M=2E/V^2. Then put this value in second equation, so now the result comes weight(W)=2E/gV^2. So,if V increases then W decreases.
So from the first equation we can get M=2E/V^2. Then put this value in second equation, so now the result comes weight(W)=2E/gV^2. So,if V increases then W decreases.
Tushita said:
1 decade ago
A little bit of physics will tell you that the speed of rotation of the earth has a direct effect on acceleration due to gravity.
And Acceleration due to gravity in turns affects the weight because weight=mass*acceleration due to gravity.
A simple equation gives us the relation between acceleration due to gravity and angular velocity of the earth which is g'=g-rw^2
Where g' = resultant acc due to gravity.
g = acc due to gravity on surface of the earth (= 9.8 m/s^2).
r = radius of the earth.
w(omega) = angular velocity of earth I.e. velocity at which earth is rotating about its axis.
This simply means that greater the w(omega) lesser would be g' and consequently lesser would be the weight.
Hope that makes things a little more clear.
P.S.The equation is derived in class 11 physics of any board.
And Acceleration due to gravity in turns affects the weight because weight=mass*acceleration due to gravity.
A simple equation gives us the relation between acceleration due to gravity and angular velocity of the earth which is g'=g-rw^2
Where g' = resultant acc due to gravity.
g = acc due to gravity on surface of the earth (= 9.8 m/s^2).
r = radius of the earth.
w(omega) = angular velocity of earth I.e. velocity at which earth is rotating about its axis.
This simply means that greater the w(omega) lesser would be g' and consequently lesser would be the weight.
Hope that makes things a little more clear.
P.S.The equation is derived in class 11 physics of any board.
Tushita said:
1 decade ago
I'm sorry if that was too technical an explanation, I do realise this was a General knowledge question but that seemed like the most legit explanation.
Rajaraman said:
1 decade ago
Dear Friends. This is all about the formula E= mc(square). Try to recall and calculate that. In short " when a body travels with the speed of light it gets converted into energy (in short mass or weight reduces) Clear?
RandomStudent said:
1 decade ago
Force(centripetal force = mvr where m is the mass of the body and v is the velocity ie speed) remains same. So when v increased, m decreases.
Mr. happy love said:
1 decade ago
Take a cosco ball and dip it in water. Take it out and slowly rotate it, and then rotate it fast, when you rotate it slow nothing will happen but when you rotate it fast water will sprinkle out.
Same is the case with earth if it starts rotating fast the objects on it will be pushed outside but the gravitational pull will hold them. Hence the weight will be reduced. :-).
Same is the case with earth if it starts rotating fast the objects on it will be pushed outside but the gravitational pull will hold them. Hence the weight will be reduced. :-).
Gauri shankar said:
10 years ago
g' = g-w^2rcos^theta.
w = Angular velocity if w increases g' decreases.
w = Angular velocity if w increases g' decreases.
Happy said:
10 years ago
@Akshay.
Its centripetal force not centrifugal that makes a body to follow circular path.
Its centripetal force not centrifugal that makes a body to follow circular path.
Abdul rahman said:
10 years ago
If spinning speed of earth decreased than weight of the body at poles does not change why?
Amrit said:
9 years ago
If the rotating speed of earth increase then our body weight will be decrease because by the acceleration of speed centrifugal force will produce which will reduce the gravity force.
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