General Knowledge - Basic General Knowledge - Discussion
Discussion Forum : Basic General Knowledge - Section 1 (Q.No. 46)
46.
Escape velocity of a rocket fired from the earth towards the moon is a velocity to get rid of the
Discussion:
8 comments Page 1 of 1.
Rishi Shrivastava said:
1 decade ago
Escape velocity is the speed that an object needs to be traveling to break free of a planet or moon's gravity well and leave it without further propulsion. For example, a spacecraft leaving the surface of Earth needs to be going 7 miles per second, or nearly 25, 000 miles per hour to leave without falling back to the surface or falling into orbit.
(1)
S.kaviarasu said:
5 years ago
The speed of the escape velocity from the gravitational field is 11.2kilo meter per second. The rocket travels at this speed or more than it. So, it will not return to the earth.
(1)
Nagraj said:
10 years ago
Escape velocity of the body from the earth is 11.2 km/s, once the object moves at the speed of 11.2 km/s, hence the object will not come back.
Omprakash said:
1 decade ago
Escape velocity of the earth is 11. 2 km/s. It is the minimum velocity with which if a body moves, it will not come back to earth again.
Kanani vishal said:
1 decade ago
It's common sense that if the object moves opposite to earth it's rid by earth's gravitational force. Cool.
Chitra said:
1 decade ago
If it doesn't get rid of earth's gravitation it would fall back to earth once the velocity becomes 0.
Tarunlatha .s said:
1 decade ago
Escape velocity of any object to get out of earth, gravitational force is 11.2 km/s.
Siddharth A said:
1 decade ago
It is 11.3km/s ... this helps the object to get release from the gravitational pull
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