Engineering Mechanics - PKRB: Work and Energy - Discussion
Discussion Forum : PKRB: Work and Energy - General Questions (Q.No. 10)
10.
THe 500-g rod AB rests along the smooth inner surface of a hemispherical bowl. If the rod is released from the position shown, determine its angular velocity 
at the instant it swings downward and becomes horizontal.
AB = 11.70 rad/sAB = 3.04 rad/sAB = 3.90 rad/sAB = 3.70 rad/sDiscussion:
1 comments Page 1 of 1.
Nishant said:
9 months ago
Good question. Give a clear description for the answer.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers