Engineering Mechanics - PKRB: Work and Energy

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Exercise : PKRB: Work and Energy - General Questions
  • PKRB: Work and Energy - General Questions
1.

A man having a weight of 180 lb sits in a chair of the Ferris wheel, which has a weight of 15,000 lb and a radius of gyration of ko = 37 ft. If a torque of M = 80(103) lb • ft is applied about O, determine the angular velocity of the wheel after it has rotated 180°. Neglect the weight of the chairs and note that the man remains in an upright position as the wheel rotates. The wheel starts from rest in the position shown.

= 0.888 rad/s
= 0.836 rad/s
= 0.874 rad/s
= 0.849 rad/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.

2.

The uniform slender rod has a mass of 5 kg. Determine the magnitude of the reaction at the pin O when the cord at A is cut and = 90°

O = 42.0 N
O = 91.1 N
O = 122.6 N
O = 67.4 N
Answer: Option
Explanation:
No answer description is available. Let's discuss.

3.

The spool of cable, originally at rest, has a mass of 200 kg and a radius of gyration of kG = 325 mm. If the spool rests on two small rollers A and B and a constant horizontal force of P = 400 N is applied to the end of the cable, compute the angular velocity of the spool when 8 m of cable has been unraveled. Neglect friction and the mass of the rollers and unraveled cable.

= 10.00 rad/s
= 12.31 rad/s
= 17.41 rad/s
= 40.0 rad/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.

4.

A chain that has a negligible mass is draped over a sprocket which has a mass of 2 kg and a radius of gyration of kO = 50 mm. If the 4-kg block A is released from rest in the position shown, s = 1 m, determine the angular velocity which the chain imparts th the sprocket when s = 2 m.

= 44.3 rad/s
= 39.6 rad/s
= 41.8 rad/s
= 59.1 rad/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.

5.

The beam having a weight of 150 lb is supported by two cables. If the cable at end B is cut so that the beam is released from rest when = 30°, determine the speed at which end A strikes the wall. Neglect friction at B. Consider the beam to be a thin rod.

vA = 5.87 ft/s
vA = 7.43 ft/s
vA = 10.18 ft/s
vA = 6.95 ft/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.