Engineering Mechanics - PKRB: Force and Animation - Discussion

Discussion :: PKRB: Force and Animation - General Questions (Q.No.2)

2. 

A clown, mounted on stilts, loses his balance and falls backward from the position, where it is assumed the = 0 when = 07deg;. Paralyzed with fear, he remains rigid as he falls. His mass including the stilts is 80 kg, the mass center is at G, and the radius of gyration about G is kG = 1.2 m. Determine the coefficient of friction between his shoes and the ground at A if it is observed that slipping occurs when = 30°.

[A]. = 0.833
[B]. = 0.468
[C]. = 0.243
[D]. = 0.400

Answer: Option D

Explanation:

No answer description available for this question.

Radhika said: (Jun 6, 2011)  
We know that, F=coefficient of friction * R

R= normal force = (80*2.5*9.81) =1962 N

F = Force = (80*9.81) N
hence,

coefficient of friction = F/R = (80*9.81)/(80*2.5*9.81)

= 0.4 ans

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