Engineering Mechanics - Planar Kinematics of a Rigid Body (PKRB) - Discussion
Discussion Forum : Planar Kinematics of a Rigid Body (PKRB) - General Questions (Q.No. 16)
16.
The disk rolls without slipping such that it has an angular acceleration of 
= 4 rad/s2 and angular velocity of 
= 2 rad/s at the instant shown. Determine the accelerations of points A and B on the link and the link's angular acceleration at this instant. Assume point A lies on the periphery of the disk, 150 mm from C.
aA = (1.200i - 0.600j) m/s2, aB = 1.650i m/s2, "AB = 1.500 rad/s2 
aA = (1.200i - 0.600j) m/s2, aB = 1.650i m/s2, "AB = 1.500 rad/s2
aA = (1.200i - 2.40j) m/s2, aB = 3.00i m/s2, "AB = 6.00 rad/s2
aA = (1.200i - 1.200j) m/s2, aB = 2.10i m/s2, "AB = 3.00 rad/s2
Discussion:
3 comments Page 1 of 1.
Ahmad said:
3 years ago
The angular velocity of link AB =0 because of the acceleration of A and B is in the same direction.
So, there is no "w".
So, there is no "w".
NIRAN said:
9 years ago
Please give the description of the answer.
Carlos said:
1 decade ago
How do we get the angular velocity of the link AB?
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