Engineering Mechanics - Planar Kinematics of a Rigid Body (PKRB)

Exercise :: Planar Kinematics of a Rigid Body (PKRB) - General Questions

  • Planar Kinematics of a Rigid Body (PKRB) - General Questions
11. 

If the block at C is moving downward at 4 ft/s, determine the angular velocity of bar AB at the instant shown.

A. TAB = 2.00 rad/s
B. TAB = 1.155 rad/s
C. TAB = 0
D. TAB = 0.870 rad/s

Answer: Option A

Explanation:

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12. 

The sphere starts from rest at = 0 and rotates with an angular acceleration of = (4) rad/s2, where is measured in radians. Determine the magnitudes of the velocity and acceleration of point P on the sphere at the instant = 6 rad.

A. vP = 96.0 in./s, aP = 1168 in./s2
B. vP = 135.8 in./s, aP = 2310 in./s2
C. vP = 83.1 in./s, aP = 1011 in./s2
D. vP = 117.6 in./s, aP = 2000 in./s2

Answer: Option C

Explanation:

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13. 

Due to an engine failure, the missile is rotating at = 3 rad/s, while its mass center G is moving upward at 200 ft/s. Determine the magnitude of the velocity of its nose B at this instant.

A. vB = 214 ft/s
B. vB = 125.0 ft/s
C. vB = 275 ft/s
D. vB = 185.4 ft/s

Answer: Option A

Explanation:

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14. 

Arm ABCD is printed at B and undergoes reciprocating motion such that = (0.3 sin 4t) rad, where t is measured in seconds and the argument for the sine is in radiaus. Determine the largest speed of point A during the motion and the magnitude of the acceleration of point D at this instant.

A. vAmax = 0.0600 m/s, aD = 1.002 m/s2
B. vAmax = 0.300 m/s, aD = 0.960 m/s2
C. vAmax = 0.0600 m/s, aD = 0.916 m/s2
D. vAmax = 0.300 m/s, aD = 0.288 m/s2

Answer: Option D

Explanation:

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15. 

At the instant shown, gear A is rotating with a constant angular velocity of A = 6 rad/s. Determine the largest angular velocity of gear B and the maximum speed of point C.

A. Bmax = 3.00 rad/s, vCmax = 0.212 m/s
B. Bmax = 6.00 rad/s, vCmax = 0.424 m/s
C. Bmax = 8.49 rad/s, vCmax = 0.600 m/s
D. Bmax = 4.24 rad/s, vCmax = 0.300 m/s

Answer: Option C

Explanation:

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