Engineering Mechanics - Moments of Inertia - Discussion
Discussion Forum : Moments of Inertia - General Questions (Q.No. 1)
1.
Determine the radius of gyration ky of the parabolic area.
Discussion:
12 comments Page 1 of 2.
Abdu said:
9 years ago
The area of semi-parabola that written in the form of x=k(y^2) or vertical semi-parabola area formula is given by 2*ab/3 so the total area will be 2*(2*ab/3) so 160*80/3= 8533 unit^2
we can take a piece of area dxdy then multiply by x^2 then integrate finally apply gyration formula.
we can take a piece of area dxdy then multiply by x^2 then integrate finally apply gyration formula.
Akbar shah said:
9 years ago
Can anyone provide the simple explanation?
Kumar saim said:
9 years ago
You are correct @Chandu.
I'm also tried in the same way, it gives the same answer as yours.
I'm also tried in the same way, it gives the same answer as yours.
Pradeep said:
10 years ago
Area of parabola 4ah/3.
Sai deep said:
10 years ago
Please give me explanation?
Jaduo said:
10 years ago
I can't understand please help me!
Kwesiga Henry said:
1 decade ago
How is the area of the figure got?
Malik said:
1 decade ago
How that I came?
Crazy man said:
1 decade ago
Ky=root over Iy/A
Iy=moment of inertia with respect to y-axis
A=area
dI=dA*r^2 (r is radius)
dI=0.1(1600-x^2)x^2 dx
Integrate both sides, limits are 0 to 40
And multiple with 2
we get
I=2730666
Here dA=y dx(here y=0.1(1600-x^2))
Integrate both sides, limits are 0 to 40
And multiple with 2
A=8533
Substitute the values of I, A in Ky we get
Ky=17.89mm
Iy=moment of inertia with respect to y-axis
A=area
dI=dA*r^2 (r is radius)
dI=0.1(1600-x^2)x^2 dx
Integrate both sides, limits are 0 to 40
And multiple with 2
we get
I=2730666
Here dA=y dx(here y=0.1(1600-x^2))
Integrate both sides, limits are 0 to 40
And multiple with 2
A=8533
Substitute the values of I, A in Ky we get
Ky=17.89mm
Chandu said:
1 decade ago
Hai frnds i solve it........
Ky=root over Iy/A
Iy=moment of inertia with respect to y-axis
A=area
dI=dA*r^2 (r is radius)
dI=0.1(1600-x^2)x^2 dx
integrate both sides,limits are 0 to 40
and multiple with 2
we get
I=2730666
here dA=y dx(here y=0.1(1600-x^2))
integrate both sides, limits are 0 to 40
and multiple with 2
A=8533
substitute the values of I,A in Ky we get
Ky=17.89mm
Ky=root over Iy/A
Iy=moment of inertia with respect to y-axis
A=area
dI=dA*r^2 (r is radius)
dI=0.1(1600-x^2)x^2 dx
integrate both sides,limits are 0 to 40
and multiple with 2
we get
I=2730666
here dA=y dx(here y=0.1(1600-x^2))
integrate both sides, limits are 0 to 40
and multiple with 2
A=8533
substitute the values of I,A in Ky we get
Ky=17.89mm
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