Engineering Mechanics - KOP: Work and Energy - Discussion
Discussion Forum : KOP: Work and Energy - General Questions (Q.No. 1)
1.
The elevator E and its freight have a total mass of 400 kg. Hoisting is provided by the motor M and the 60-kg block C. If the motor has an efficiency of e = 0.6, determine the power that must be supplied to the motor when the elevator is hoisted upward at a constant speed of vE = m/s.
Discussion:
4 comments Page 1 of 1.
Lakshmipathi said:
8 years ago
How you got Ve = 4?
Binth ismail said:
9 years ago
@Chirag.
How do you get Ve = 4?
How do you get Ve = 4?
CHIRAG SETHI said:
10 years ago
Mc = 60.
g = 9.8.
Me = 400.
E = 0.6.
Ve = 4 must be to get an answer.
F = (ME-MC)g.
Power = FV/E.
So Power = 22.2 KW.
g = 9.8.
Me = 400.
E = 0.6.
Ve = 4 must be to get an answer.
F = (ME-MC)g.
Power = FV/E.
So Power = 22.2 KW.
Gokul Krsishnan said:
10 years ago
Please tell me the method used for solving this question.
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