Engineering Mechanics - KOP: Work and Energy - Discussion
Discussion Forum : KOP: Work and Energy - General Questions (Q.No. 7)
7.
A motor hoists a 50-kg crate at constant speed to a height of h = 6 m in 3 s. If the indicated power of the motor is 4 kw, determine the motor's efficiency.
Discussion:
1 comments Page 1 of 1.
Kyu said:
1 decade ago
Given constant speed, the energy of the weight at height h=6m (dist moved in 3s is),
E=mgh = 50 * 9.8 * 6/3 = 980 N m/s.
Efficiency, e = Output/Input * 100%
= 980/ 4000 * 100.
= 24.5%.
E=mgh = 50 * 9.8 * 6/3 = 980 N m/s.
Efficiency, e = Output/Input * 100%
= 980/ 4000 * 100.
= 24.5%.
(1)
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