Engineering Mechanics - KOP: Impulse and Momentum - Discussion
Discussion Forum : KOP: Impulse and Momentum - General Questions (Q.No. 10)
10.
The two handcars A and B each have a mass of 80 kg. Both cars are initially at rest. Both cars start from rest before the man jumps. If the man C has a mass of 70 kg and jumps from A with a horizontal relative velocity of vC/A = 2 m/s and lands on B, determine the velocity of each car after the jump. Neglect the effects of rolling resistance.
Discussion:
1 comments Page 1 of 1.
Alexander said:
4 years ago
Ma = 80 kg Mb = 80kg Mc = 70 kg.
Va1 = 0m/s
Vb1 = 0 m/s
Vc = 2m/s.
Va2 = ?
Vb 2 = ?.
Vb2 ==>
Mb * Vb + Mc * Vc = Mb+c * Vb2.
80kg *0 + 70kg*2m/s = 150kg * Vb2.
Vb2 = 140/150.
Vb2 = 0.9333 m/s.
Va2 ==>
80*0.93 ==> 74.4.
70* (2-0.93) ==> 74.9.
Va2 = 74.9-74.4 ==> 0.5m/s.
Va1 = 0m/s
Vb1 = 0 m/s
Vc = 2m/s.
Va2 = ?
Vb 2 = ?.
Vb2 ==>
Mb * Vb + Mc * Vc = Mb+c * Vb2.
80kg *0 + 70kg*2m/s = 150kg * Vb2.
Vb2 = 140/150.
Vb2 = 0.9333 m/s.
Va2 ==>
80*0.93 ==> 74.4.
70* (2-0.93) ==> 74.9.
Va2 = 74.9-74.4 ==> 0.5m/s.
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