Engineering Mechanics - KOP: Impulse and Momentum - Discussion
Discussion Forum : KOP: Impulse and Momentum - General Questions (Q.No. 12)
12.
A 0.6-kg brick is thrown into a 25-kg wagon which is initially at rest. If, upon entering, the brick has a velocity of 10 m/s as shown, determine the final velocity of the wagon.
Discussion:
1 comments Page 1 of 1.
Akil said:
9 years ago
Change in momentum = (M+m)v - mu = 0
m= 0.6 M = 25 u(horizontal component )= 10 cos 30.
(M+m)v = mu.
(25+0.6)v = 0.6 * 10 cos 30.
v = 0.6* 10 cos 30/25.6.
v = 0.20297 (approx = 0.203).
m= 0.6 M = 25 u(horizontal component )= 10 cos 30.
(M+m)v = mu.
(25+0.6)v = 0.6 * 10 cos 30.
v = 0.6* 10 cos 30/25.6.
v = 0.20297 (approx = 0.203).
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