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Engineering Mechanics - KOP: Force and Acceleration - Discussion

Discussion Forum : KOP: Force and Acceleration - General Questions (Q.No. 9)
KOP: Force and Acceleration
9.

A tobbogan and rider have a total mass of 100 kg and travel down along the (smooth) slope defined by the equation y = 0.2x2. At the instant x = 8 m, the toboggan's speed is 4 m/s. At this point, determine the rate of increase in speed and the normal force which the toboggan exerts on the slope. Neglect the size of the toboggan and rider for the calculation.

at = 8.32 m/s2, N = 520 N
at = 8.32 m/s2, N = 537 N
at = 9.36 m/s2, N = 310 N
at = 9.36 m/s2, N = 293 N
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.
Azam said:   8 years ago
Rad of curvature is not 0.
An = v^2/p ----> p= some number &v is given.
Fikri said:   1 decade ago
Hi, Can you give me a solution how to get at = 9.36 m/s2, N = 310 N.Tq?
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