Engineering Mechanics - Kinematics of Particle (KOP) - Discussion
Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 28)
28.
The block B is suspended from a cable that is attached to the block at E, wraps around three pulleys, and is tied to the back of a truck. If the truck starts from rest when xD is zero, and moves forward with a constant acceleration of aD = 2 m/s2, determine the speed of the block at the instant xD = 3 m.
Discussion:
3 comments Page 1 of 1.
Sonakshi said:
7 years ago
At instant 3 xb+root of xd ^2 +16=L.
3vb+xd/ √16+xd^2 dxd/dt=0.
So,vb=0.6m/s.
3vb+xd/ √16+xd^2 dxd/dt=0.
So,vb=0.6m/s.
Bhokaal said:
8 years ago
Find the velocity of a truck at Xd=3 which is root12 then find the velocity of string AD which is 3root (12/34).
So, the velocity of the block will be a velocity of AD divided by 3, hence answer is 0.594.
So, the velocity of the block will be a velocity of AD divided by 3, hence answer is 0.594.
Jim said:
9 years ago
How?
Explain.
Explain.
(1)
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