Engineering Mechanics - Kinematics of Particle (KOP) - Discussion
Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 12)
12.
If the end of the cable at A is pulled down with a speed of 2 m/s, determine the speed at which block B arises.
vB = 4.00 m/s 
vB = 1.000 m/s 
vB = 1.000 m/s
vB = 4.00 m/s
Discussion:
1 comments Page 1 of 1.
Eno said:
6 years ago
According to the number of strings in pulley B and the side A.
The equation of dependency would be:
XA+2XB= C.
: . VA + 2VB =0,
: . VB=-VA /2,
VB = -2/2 =-1m/s.
But the direction if the positive velocity VA is downwards, therefore, the negative velocity would be upward, So, the answer is B.
The equation of dependency would be:
XA+2XB= C.
: . VA + 2VB =0,
: . VB=-VA /2,
VB = -2/2 =-1m/s.
But the direction if the positive velocity VA is downwards, therefore, the negative velocity would be upward, So, the answer is B.
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