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Engineering Mechanics - Kinematics of Particle (KOP) - Discussion

Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 23)
Kinematics of Particle (KOP)
23.

A car travels up a hill with the speed shown in the graph. Compute the total distance the car moves until it stops at t = 60 s. What is the acceleration at t = 45 s?

s = 400 m, a45 = -3.00 m/s2
s = 450 m, a45 = -0.333 m/s2
s = 400 m, a45 = -3.00 m/s2
s = 450 m, a45 = 0.333 m/s2
Answer: Option
Explanation:
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Discussion:
1 comments Page 1 of 1.
Vaibhav said:   9 years ago
d = v * t (i.e. area under the curve will give the total distance traveled).
d = (10 * 30) + ((1/2) * 10 * (60 - 30)) = 450.
acc = (v2 - v1)/t = -0.33.
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