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Engineering Mechanics - Internal Forces - Discussion

Discussion Forum : Internal Forces - General Questions (Q.No. 2)
Internal Forces
2.

The work platform supports an 80-kg man having a mass center at G. Determine the axial force, shear force, and bending moment at point E of the telescopic column AB due to the load of the man only.

AE = 785 N C, VE = 0, ME = 785 N-m
AE = 785 N C, VE = 392 N, ME = 0
AE = 785 N T, VE = 392 N, ME = 0
AE = 785 N T, VE = 0, ME = 785 N-m
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
2 comments Page 1 of 1.
Kartik said:   8 years ago
Yes, the force is eccentric but we can replace it by the axial force and moment.
Sheel said:   1 decade ago
Moment about E = 80*9.81*1.
= 785Nm.

Axial force = 80*9.81N.
No shear force.
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